For primitive types, when calling a method, the type is previously converted (boxed) to a reference type and then the method is called. This means that for primitive types a == b will yield the same value as a.equals(b), but in the latter case two temporary boxed objects are created prior to calling the equals() method. This will make the
99 4. A code-only answer is not high quality. While this code may be useful, you can improve it by saying why it works, how it works, when it should be used, and what its limitations are. Please edit your answer to include explanation and link to relevant documentation. – Stephen Ostermiller.

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A workable approach to handle that situation may be to have the base type implement an equals2 method, which return 1 if its special knowledge of the other object meant it could tell it was equal, -1 if it could tell it was not equal, or 0 if it couldn't tell. If either type's equals2 method knows they're unequal, they're unequal. Otherwise, if In Java, the equals() the method is used to determine if two objects are equal. It is defined in the Object class, which is the root of the Java class hierarchy, and it is inherited by all Java
Another option is the Objects.equals utility method. Objects.equals( thisEnum , thatEnum ) Objects.equals for null-safety. equals operator == instead of .equals() Which operator is the one I should be using? A third option is the static equals method found on the Objects utility class added to Java 7 and later. Example. Here’s an example
Add a comment. 7. The difference between equals () and compareTo () is that equals () just checks if two objects are equal to each other where the compareTo () is used to identify the natural order of the instances of specified class. Also equals () method has a contract with hashCode () method but compareTo () hasn't. According to JavaDoc:
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    • how to use equals method in java